Suppose e x 5 5 and e x x 2 1 5 27.5. what is
WebJul 19, 2016 · Instead, it should have said. E [ X E [ X]] = E [ X] E [ X]. The justification is this: E [ X ⋅ 5] = 5 E [ X] and similarly for any other constant besides 5. And in this context, "constant" means "not random". So just treat E X the same way you … WebDivide f-2, the coefficient of the x term, by 2 to get \frac{f}{2}-1. Then add the square of \frac{f}{2}-1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
Suppose e x 5 5 and e x x 2 1 5 27.5. what is
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WebAnswer to Solved Suppose E(X) = 5 and E[X(X – 1)] = 27.5. (a) What is. This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Web1.5.5 Explain the relationship between exponential and logarithmic functions. 1.5.6 Describe how to calculate a logarithm to a different base. 1.5.7 Identify the hyperbolic functions, their graphs, and basic identities. In this section we examine exponential and logarithmic …
Weba+bx2 0 ≤ x ≤ 1 0 otherwise If E[X] = 3 5, find a and b. Solution. First, f(x) is a probability density function. Z ... The expected lifetime of such a tube is 2. 5.21 (6 points) Suppose that the height, in inches, of a 25-year-old man is a normal random WebSuppose you play a game of chance in which five numbers are chosen from 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. A computer randomly selects five numbers from zero to nine with replacement. You pay $2 to play and could profit $100,000 if you match all five numbers in order (you get …
WebSuppose E ( X) = 5 E [ X ( X - 1)] = 27.5 What is a. E ( X2 )? [ Hint: E [ X ( X - 1)] = E [ X2 - X] = E ( X2) - E ( X)]? b. V ( X )? c. The general relationship among the quantities E ( X ), E [ X ( X - 1)], and V (X)? Step-by-step solution 99% (120 ratings) for this solution Step 1 of 5 (a) Given … WebSep 6, 2024 · So, if we have that E [X (X − 1)] = 27.5, we can write them using the first property as: E (X (X − 1)) = 27.5 E (X 2 − X) = 27.5 E (X 2) − E (X) = 27.5 Then, replacing E (X) by 5 and solving for E (X 2) we get: E (X 2) − 5 = 27.5 E (X 2) = 27.5 + 5 E (X 2) = 32.5 …
WebAug 22, 2016 · Explanation: ex−1 −5 = 5. ex−1 = 10. x − 1 = ln10. x − 1 ≅2.30258. x ≅3.30258. Answer link.
WebSuppose E(X)=5 and E[X(X-1)]=27.5. E[X(X-1)]= E[X2]-E[X]= E[X2]-5=27.5 Find E(X2) =32.5 Find Var(X)=32.5-25=7.5 3. Let X denote the amount of time for which a book on 2-hour reserve at a college library is checked out by a randomly selected student and suppose … homes in bearpaw lakeWebSuppose a particular population of bacteria is known to double in size every 4 hours. If a culture starts with 1000 bacteria, the number of bacteria after 4 hours is n(4) = 1000 · 2. The number of bacteria after 8 hours is n(8) = n(4) · 2 = 1000 · 22. In general, the number of bacteria after 4m hours is n(4m) = 1000 · 2m. homes in bear creek ncWebAlgebra. Simplify (x+5) (x-5) (x + 5) (x − 5) ( x + 5) ( x - 5) Expand (x+5)(x− 5) ( x + 5) ( x - 5) using the FOIL Method. Tap for more steps... x⋅x+x⋅ −5+5x+5⋅−5 x ⋅ x + x ⋅ - 5 + 5 x + 5 ⋅ - 5. Simplify terms. Tap for more steps... x2 − 25 x 2 - 25. homes in beaufort for cheapWebMoving down to the one only sister on the bottom Left in the same direction current. So we subtract already potential drop off two times one just to bypassed e m f e two from plus to minus. So we got a subject ratey m If finally the last two resistor times to just for we create ist with zero, you should be able to identify e to to be seven volts. hiring practices in canadaWeb1.Suppose that the number of plants of a particular type found in a rectangular sampling region (called a quadrat by ecologists) in a certain geographic area is a random variable Xwith pmf P(X= x) = (c xa x= 1 ;2 3::: 0 otherwise: (a)Let a= 3. Is E(X) nite? Justify your answer. (b)Let a= 2. Is E(X) nite? Justify your answer. hiring practices lawWebSuppose x takes on the values x = 1, 1.2, 1.4, . . . , 5. Use MATLAB to compute the array y that results from the function y = 7 sin(4x). Use MATLAB to determine how many elements are in the array y and the value of the third element in the array y. Suppose that x = 3 and y = 4. Use MATLAB to compute the following, and check the results with a ... hiring power toolsWebApr 8, 2016 · V(aX 1 b) 5 a 2 s 2 X . [Hint: With , h(X) 5 aX 1 b X has pmf E[h(X)] 5 am 1 b where .] m 5 E(X) 1n x 5 1, 2, 3, . . . , n 42. Suppose and E(X) 5 5 E[X(X 2 1)] 5 27.5 . What is p(x) 5 e 2 2 0 otherwise hiring practices lawyer